SQL自定义函数split分隔字符串

作者:佚名 和mssql相关  

一、F_Split:分割字符串拆分为数据表

Create FUNCTION [dbo].[F_Split]
 (
     @SplitString nvarchar(max),  --源字符串
     @Separator nvarchar(10)=' '  --分隔符号,默认为空格
 )
 RETURNS @SplitStringsTable TABLE  --输出的数据表
( [id] int identity(1,1), [value] nvarchar(max) ) AS BEGIN DECLARE @CurrentIndex int; DECLARE @NextIndex int; DECLARE @ReturnText nvarchar(max); SELECT @CurrentIndex=1; WHILE(@CurrentIndex<=len(@SplitString)) BEGIN SELECT @NextIndex=charindex(@Separator,@SplitString,@CurrentIndex); IF(@NextIndex=0 OR @NextIndex IS NULL) SELECT @NextIndex=len(@SplitString)+1; SELECT @ReturnText=substring(@SplitString,@CurrentIndex,@NextIndex-@CurrentIndex); INSERT INTO @SplitStringsTable([value]) VALUES(@ReturnText); SELECT @CurrentIndex=@NextIndex+1; END RETURN; END --使用示例 select * FROm dbo.F_Split('111,b2222,323232,32d,e,323232f,g3222', ',')

结果为

id          value

-------- ---------------------------------------

1           111

2           b2222

3           323232

4           32d

5           e

6           323232f

7           g3222


=========================================================================

二、F_SplitLength:获取分割后的字符数组的长度

Create function [dbo].[F_SplitLength]
 (
  @String nvarchar(max),  --要分割的字符串
  @Split nvarchar(10)  --分隔符号
 )
 returns int
 as
 begin
  declare @location int
  declare @start int
  declare @length int
  
  set @String=ltrim(rtrim(@String))
  set @location=charindex(@split,@String)
  set @length=1
  while @location<>0
  begin
    set @start=@location+1
    set @location=charindex(@split,@String,@start)
    set @length=@length+1
  end
  return @length
 end

--调用示例
select dbo.F_SplitLength('111,b2222,323232,32d,e,323232f,g3222',',')

结果为7。

 

=========================================================================

三、F_SplitOfIndex:获取分割后特定索引的字符串

Create function [dbo].[F_SplitOfIndex]
 (
  @String nvarchar(max),  --要分割的字符串
  @split nvarchar(10),  --分隔符号
  @index int --取第几个元素
 )
 returns nvarchar(1024)
 as
 begin
  declare @location int
  declare @start int
  declare @next int
  declare @seed int
  
  set @String=ltrim(rtrim(@String))
  set @start=1
  set @next=1
  set @seed=len(@split)   
  set @location=charindex(@split,@String)
  
  while @location<>0 and @index>@next
  begin
    set @start=@location+@seed
    set @location=charindex(@split,@String,@start)
    set @next=@next+1
  end
  if @location =0 select @location =len(@String)+1   
  return substring(@String,@start,@location-@start)
 end

--使用示例
select dbo.F_SplitOfIndex('111,b2222,323232,32d,e,323232f,g3222',',', 3)

结果为323232。

 

转自:http://www.cnblogs.com/xiaofengfeng/archive/2012/06/01/2530930.html

 

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